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#1 seraz ?
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Posted Yesterday, 08:32 PM
this is my coding...for this coding my result should be 6 iteration only...
im not very sure whether my answer in rad or deg...
ples someone help me...
#include<stdio.h> #include<math.h> #include<stdlib.h> #define true 1; #define false 0; main() { int i,m,OK,it; double c,d,TOL,fx[100],dfx[100],a[100],x[100]; x[0]=2.3,i=0; TOL=(pow(10,-32)); m=2; fx[0]=pow((pow(sin(x[0]),2)-pow(x[0],2)+1),2); d=fabs(fx[0]); printf("%d %.12e %.12e\n",i,x[0],d); OK=false; it=0; i=0; while(!OK) { it=it+1; fx[i]=pow((pow(sin(x[i]),2)-pow(x[i],2)+1),2); dfx[i]=2*(pow(sin(x[i]),2)-pow(x[i],2)+1)*(2*sin(x[i])*cos(x[i])-2*x[i]); x[i+1]=x[i]-(m*(fx[i]/dfx[i])); fx[i+1]=pow((pow(sin(x[i+1]),2)-pow(x[i+1],2)+1),2); c=fabs(fx[i+1]); printf("%d %.12e %.12e\n",i+1,x[i+1],c); if(c<TOL) OK=true; i=i+1; } }
This post has been edited by Skydiver: Yesterday, 08:42 PM
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Replies To: answer in deg and rad
#2 Skydiver ? 
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Re: answer in deg and rad
Posted Yesterday, 08:54 PM
Try increasing your tolerance to 10-30 instead of 10-32.This post has been edited by Skydiver: Yesterday, 08:55 PM
#3 seraz ?
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Re: answer in deg and rad
Posted Yesterday, 09:25 PM
Try increasing your tolerance to 10-30 instead of 10-32.
i cannot do that...
because it already fit in my project...
i want to observe the number of iteration with same TOL but different test function
#4 Skydiver ?
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Re: answer in deg and rad
Posted Yesterday, 09:38 PM
Well, base on the values of C, I don't see how you will ever get a value of c less than 10-32 in 6 iterations.Here's the output I'm seeing:
0 2.300000000000e+000 1.394218647024e+001 1 1.632475867168e+000 4.472626765749e-001 2 1.435079952458e+000 6.046710267708e-003 3 1.405195569536e+000 3.057005611515e-006 4 1.404492036112e+000 9.272594171137e-013 5 1.404491648215e+000 8.590695257857e-026 6 1.404491648215e+000 1.109335647967e-031 7 1.404491648215e+000 1.972152263053e-031 8 1.404491648215e+000 1.109335647967e-031 9 1.404491648215e+000 1.972152263053e-031 10 1.404491648215e+000 1.109335647967e-031 11 1.404491648215e+000 1.972152263053e-031 12 1.404491648215e+000 1.109335647967e-031 13 1.404491648215e+000 1.972152263053e-031 : until it overruns the buffers you declared.
How did you determine that 6 iterations was going to be sufficient?
This post has been edited by Skydiver: Yesterday, 09:43 PM
#5 Skydiver ?
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Re: answer in deg and rad
Posted Yesterday, 09:46 PM
Perhaps use GMP or MPIR as your number and math library instead of the standard C/C++ library to get more precision and perhaps get past the repetition that is happening above.
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